9y^2-96y+252=0

Solution for 9y^2-96y+252=0 equation:

9y^2-96y+252=0

a = 9; b = -96; c = +252;
Δ = b2-4ac
Δ = -962-4·9·252
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-12}{2*9}=\frac{84}{18}
=4+2/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+12}{2*9}=\frac{108}{18}
=6
$